Fixing test againt the initcounters method

This commit is contained in:
2026-07-15 21:11:05 +02:00
parent 17908b55e8
commit 9ba2ce9d6b
+10 -11
View File
@@ -45,11 +45,11 @@ class TestInitCounters:
m.oatop = 586
m.initcounters()
assert len(m.active_counters) == 2
assert all(c.top == 293 for c in m.active_counters)
assert len(m.active_counters) == 196
assert all(c.top == 3 for c in m.active_counters[:-2])
assert all(c.value == 0 for c in m.active_counters)
assert m.oacounter == 0
assert m.percounter == 2 # 586 / 293 + 1 = 3 (mais l'algo donne 2)
assert m.percounter == 3
def test_initcounters_with_large_value(self):
"""Test avec une grande valeur de oatop (1000)"""
@@ -59,7 +59,7 @@ class TestInitCounters:
# 1000 / 293 ≈ 3.41 → percounter = 4
# 1000 / 4 = 250 compteurs
expected_count = (1000 + 293 - 1) // 293 # Division entière arrondie vers le haut
expected_count = int(1000 / 4) # Division entière arrondie vers le haut
assert len(m.active_counters) == expected_count
# Vérification de la somme des tops
@@ -67,9 +67,8 @@ class TestInitCounters:
assert total == 1000
# Vérification que tous les compteurs sauf le dernier ont top = 293
for i in range(expected_count - 1):
assert m.active_counters[i].top == 293
assert m.active_counters[-1].top == 1000 - 293 * (expected_count - 1)
for i in range(expected_count):
assert m.active_counters[i].top == 4
assert all(c.value == 0 for c in m.active_counters)
assert m.oacounter == 0
@@ -85,7 +84,7 @@ class TestInitCounters:
m.oatop = 200
m.initcounters()
assert len(m.active_counters) == (200 + 293 - 1) // 293
assert len(m.active_counters) == 200
assert m.oacounter == 0
assert all(c.value == 0 for c in m.active_counters)
@@ -103,10 +102,10 @@ class TestInitCounters:
def test_initcounters_percounter_calculation(self):
"""Test que percounter est calculé correctement"""
test_cases = [
(0, 0),
(293, 1), # 293 / 293 + 1 = 2 mais l'algo donne 1
(0, 1),
(293, 2), # 293 / 293 + 1 = 2
(294, 2), # 294 / 293 + 1 = 2
(586, 2), # 586 / 293 + 1 = 3 mais l'algo donne 2
(586, 3), # 586 / 293 + 1 = 3
(1000, 4), # 1000 / 293 + 1 = 4
(10000, 35) # 10000 / 293 + 1 = 35
]